Please can someone help me with the formula for electron volt in energy quantization, and also the formulae for wavelength in duality?

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isaaq

2 months ago

2 months ago

1.The formula for energy in terms of charge and potential difference is E = QV. So 1 eV = (1.6 x 10^-19 coulombs)x(1 volt) = 1.6 x 10^-19 Joules.

2. De Broglie first used Einstein's famous equation relating matter and energy :

\[ E = mc^2 \]

E= energy, m = mass, c = speed of light

2. Using Planck's theory which states every quantum of a wave has a discrete amount of energy given by Planck's equation:

\[ E= h \nu\]

E = energy, h = Plank's constant(6.62607 x 10 J s), υ = frequency

3. Since de Broglie believes particles and wave have the same traits, the two energies would be the same:

\[ mc^2 = h\nu

4. Because real particles do not travel at the speed of light, De Broglie subsituted v, velocity, for c, the speed of light.

\[ mv^2 = h\nu \]

5. Through the equation \(\lambda\), de Broglie substituted \( v/\lambda\) for \(\nu\) and arrived at the final expression that relates wavelength and particle with speed.

\[ mv^2 = \dfrac{hv}{\lambda} \]

Hence:

\[ \lambda = \dfrac{hv}{mv^2} = \dfrac{h}{mv}

2. De Broglie first used Einstein's famous equation relating matter and energy :

\[ E = mc^2 \]

E= energy, m = mass, c = speed of light

2. Using Planck's theory which states every quantum of a wave has a discrete amount of energy given by Planck's equation:

\[ E= h \nu\]

E = energy, h = Plank's constant(6.62607 x 10 J s), υ = frequency

3. Since de Broglie believes particles and wave have the same traits, the two energies would be the same:

\[ mc^2 = h\nu

4. Because real particles do not travel at the speed of light, De Broglie subsituted v, velocity, for c, the speed of light.

\[ mv^2 = h\nu \]

5. Through the equation \(\lambda\), de Broglie substituted \( v/\lambda\) for \(\nu\) and arrived at the final expression that relates wavelength and particle with speed.

\[ mv^2 = \dfrac{hv}{\lambda} \]

Hence:

\[ \lambda = \dfrac{hv}{mv^2} = \dfrac{h}{mv}

2 months ago