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The force of repulsion between two point positive charge 5nf and 8nf separated by a...

The force of repulsion between two point positive charge 5nf and 8nf separated by a distance of 0.02m apart?

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Answers (4)

Michael
1 week ago
F=(q¹*q²/r²)*9*10^9
F=(5*10^-9*8*10^-9/0.02)9*10^9
F=90J
DAVID OKORO UKEH
1 week ago
0.0009Newton
DAVID OKORO UKEH
1 week ago
The formula is F=(Kq1q2/r^2),where K is a constant.
DAVID OKORO UKEH
1 week ago
The formula is F=(Kq1q2/r^2),where K is a constant.(K=9.0*10^9)
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