1. Describe the changes to the magnitude & direction of the force on one, if...

1. Describe the changes to the magnitude & direction of the force on one, if the charges in an electric dipole when the distance b/w the charges increase.
2. If a positively charge rod is held close to top of the brass cap of an electrician, the leaf of the electroscope spread apart, this is due to excess of what type of charge in the leaf?
3. If a positively charged rod is brought close to brass cap of negatively charged electroscope. What happen to the leaf of the electroscope?
4. Suppose that two point charges each with a charge of +1 coloumb as separated by distance of 1m (a) will there attract or repel each other (b) determine the magnitude of electrical force b/w them.
5. Two particle are charged with an identical quantity & type of charge of -0.0025πC. There are held apart at a separation distance of 8m. Determine the magnitude of electric force of repulsion b/w them.
6. Two charged boxes are 1m apart from each other, the built box has a charge of 0.000337C and is attracting a red box with 6262N, determine the charge of the red box.
7. Two coins lying 1.5m apart on a table, they are carrying identical charges. Approximately how fast is charge in each coin, if each coin display a box of 2.0m/s.?

To get notifications when anyone posts a new answer to this question,
Follow New Answers

Post an Answer

Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here

Answers (1)

Emmanol
1 month ago
*repulsion
*if a positively charge rod is held close to top of the brass cap of an electrician,the leaf of the electroscope spread apart(diverge),this is due to exess of test charge which are the same.
*if a positively charge rod is brought close to brass cap of negatively charged electroscope the leaf of the electroscope divergence decreses.
*if two bodies have the same charge(+1),the force is that of repulsion.
*two bodies of +1c each with a distance of 1m apart take 1/4pie€¤(constant) as
9.0*10^9Nm^2C^-2
r(distance)
SINCE q1=q2=q
constant *q^2/r^2
9*10^9*1^2/1^2
FORCE=9*10^9N

*CHARGE=-0.0025C
r=8m
f=constant*q^2/r^2
f=9*10*(0.0025)^2/8^2
FORCE=8.78*10^-7N

*q1 rep B(0.000337C)
q2 rep R
r=1meter
F=6262N
F=9*10^9 * q1q2/r^2
6262=9*10^9 * 0.000337 * R DIVIDED BY 1
6262=3.03 *10^6 * R
R(q2)=2066.6C
Ask Your Own Question

Quick Questions

See More Physics Questions