A body is projected at an angle of 30° to the horizontal with a velocity of 150 ms\(^{-1.}\). Calculate the time it takes to reach the greatest height [Take g = 10 ms\(^2\) and neglect air resistance]
Given Data: u = 150 ms\(^{-1.}\), Ø = 30°
Time of Flight = \(\frac{2usinØ}{g}\) → \(\frac{2 * 150 * sin30°}{10}\)
= 15s
t = time taken to reach maximum height = ?
t = usinθ ÷g
t = [150 × sin(30)] ÷10
t = 7.5secs.
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