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Four resistors R\(_1\),R\(_2\),R\(_3\), and R\(_4\) are connected in series as shown above, V\(_1\),V\(_2\),V\(_3\) are voltmeters...

Physics
JAMB 1983

Four resistors R\(_1\),R\(_2\),R\(_3\), and R\(_4\) are connected in series as shown above, V\(_1\),V\(_2\),V\(_3\) are voltmeters connected as indicated above. Which of the following relations is correct??

  • A. V1 = V3 =V2/2
  • B. V1 = 2V2 = V3
  • C. V1=1/2V3 =V3
  • D. V2 - V1 = V3
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Correct Answer: Option A
Explanation

From the diagram: The four resistors (\(R_1, R_2, R_3, R_4\)) are in series, so the same current (I) flows through all of them.

The voltmeters are connected as follows:

Voltmeter Measures the voltage across
\(V_1\) \(R_1\)
\(V_2\) \(R_2 + R_3\)
\(V_3\) \(R_4\)

Using Ohm’s Law:

V = IR

So, \(V_1 = IR_1\)

\(V_2 = I(R_2 + R_3)\)

\(V_3 = IR_4\)

In this type of  question, the resistors are usually assumed equal:

\(R_1 = R_2 = R_3 = R_4\) = R

Calculate the voltages

\(V_1\) = IR
\(V_2\) = I(R + R) = 2IR
\(V_3\) = IR

Compare them

\(V_1 = V_3\)

and \(V_2 = 2V_1\)
]Therefore: \(V_1 = V_3 = \frac{V_2}{2}\)


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