Correct Answer: Option B

Explanation

The 2\(\Omega\) resistors are in parallel

R\(_{para}\) = \(\frac{R_1 \times R_2}{R_1 + R_2}\) = \(\frac{2 \times 2}{2 + 2}\) = \(\frac{4}{4}\) = 1 \(\Omega\)

This 1  \(\Omega\) resistor is in series with both the 4  \(\Omega\) and 3 \(\Omega\) resistors

Therefore, R\(_{total}\) = 1 + 4 + 3 = 8 \(\Omega\)

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