Correct Answer: Option D

Explanation

Let the masses of the two objects be M1 and M2
and their distance apart = r

Therefore the force acting F1 = \( \frac{GM1M2}{r^2}\)

for a new distance of r/2, we have a force of

F2 = \( \frac{GM2M2}{r/2}\)

\(\text{Thus } F1 \times r^2 = GM_1M_1 \text{and}\)
F2 \(\times (r/2)^2 = GM_1M_1\)

\(\text{Since } GM1M1 = GM_1M_1\)

\(\implies F_1 \times r^2 = F2 \times (r/2)^2\)

\(\text{Therefore } 200 \times r^2 = F2 \times r^2/4\)

F2 = \(\frac{4 \times 200 \times r^2}{r^2} = 800N\)

There is an explanation video available below.

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