Correct Answer: Option A

Explanation

In general, the velocity of sound in air varies directly as the square root of temperature measured in kelvin.

That V \( \propto \sqrt{T} \implies V^2 \propto T.\)

\(\text{Therefore} \frac{V^2_1}{T_1} = \frac{V^2_2}{T_2}\)

\(\text{Thus Let } V_1\) = 4m/s 
T\(_1\) = 10K 
\(\text{Therefore } V_2 = 2V_1\) = 8m/s 

\(\implies \frac{4^2}{10} = \frac{8^2}{T_2}\)

T\(_2 = \frac{64 \times 10}{16}\) = 40K

T\(_2 = 4T_1 \)

Thus, when the velocity of sound in air is doubled, its absolute temperature will be quadrupled.

There is an explanation video available below.

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