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What is the difference in the amount of heat given out by 4kg of steam...

Physics
JAMB 1991

What is the difference in the amount of heat given out by 4kg of steam and 4kg of water when both are cooled from 100ºC to 80ºC? [the specific latent heat of steam is 2,260,000Jkg\(^{-1}\), specific heat capacity of water is 4200Jkg\(^{-1}\)K\(^{-1}\)]

  • A. 4200J
  • B. 2,260,OOOJ
  • C. 9,040,000J
  • D. 9,380,000J
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Correct Answer: Option C
Explanation

To find the difference in the amount of heat given out by 4 kg of steam and 4 kg of water when both are cooled from 100°C to 80°C, we need to calculate the heat released by each.

Heat Given Out by Water

The heat given out by water as it cools can be calculated using the formula:

\(Q = mc\Delta T\)

Where:
-  m = 4 kg (mass of water)
-  c = 4200  (specific heat capacity of water)
- \( \Delta\) T = 100 - 80 = 20K (change in temperature)

Calculating the heat given out by water:

\(Q_{\text{water}} = 4 \times 4200 \times 20 = 336,000 \, \text{J}\)

 Heat Given Out by Steam

For steam, we need to consider both the cooling of the steam to water and the cooling of the water from 100°C to 80°C. The total heat given out by the steam is the sum of the heat released during condensation and the heat released during cooling.

Heat released during condensation: \(Q_{\text{condensation}} = mL\)

Where:
- \( L = 2,260,000 \, \text{J/kg} \) (specific latent heat of steam)

Calculating the heat released during condensation:

\(Q_{\text{condensation}} = 4 \, \text{kg} \times 2,260,000 \, \text{J/kg} = 9,040,000 \, \text{J}\)

Heat released by water as it cools from 100°C to 80°C:

This is the same calculation we did for water above:

\(Q_{\text{cooling}} = 4 \times 4200  \times 20  = 336,000 \, \text{J}\)

Total heat given out by steam:

\(Q_{\text{steam}} = Q_{\text{condensation}} + Q_{\text{cooling}} = 9,040,000 \, \text{J} + 336,000 \, \text{J} = 9,376,000 \, \text{J}\)

Difference in Heat Given Out

Now, we find the difference in heat given out by steam and water:

\(\text{Difference} = Q_{\text{steam}} - Q_{\text{water}} = 9,376,000 \, \text{J} - 336,000 \, \text{J} = 9,040,000 \, \text{J}\)

The difference in the amount of heat given out by 4 kg of steam and 4 kg of water when both are cooled from 100°C to 80°C is 9,040,000 J.


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