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 Factorize completely \(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8}\)

Mathematics
JAMB 2010

 Factorize completely \(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8}\)

  • A.
    x(x-5)
    2(x+2)
  • B.
    x(x-5)
    2(x-2)
  • C.
    x(x+5)
    2(x+2)
  • D.
    x2+5
    2x+4
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Correct Answer: Option C
Explanation

\(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8} = \frac{x(x^{2} + 3x - 10)}{2(x^{2} - 4)}\)

= \(\frac{x(x^{2} - 2x + 5x - 10)}{2(x - 2)(x + 2)}\)

= \(\frac{x(x - 2)(x + 5)}{2(x - 2)(x + 2)}\)

= \(\frac{x(x + 5)}{2(x + 2)}\)

 

 

 

 

 

 

 

There is an explanation video available below.


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Explanation Video

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JAMB CBT Mobile App 2024 - Free Download
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
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JAMB CBT Mobile App 2024 - Free Download
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
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