If P = [\(\frac{Q(R - T)}{15}\)] \(\frac{1}{3}\) make T the subject of the relation
Taking the cube of both sides of the equation give
P\(^3\) = \(\frac{Q(R - T)}{15}\)
Cross multiplying
15P\(^3\) = Q(R - T)
Divide both sides by Q
\(\frac{15P^3}{Q}\) = R - T
Rearranging gives
T = R - \(\frac{15P^3}{ Q}\)
= \(\frac{QR - 15P^3}{Q}\)
Answer is C
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