A bag contains 5 red and 4 blue identical balls. Id two balls are selected...

WAEC 2016

A bag contains 5 red and 4 blue identical balls. Id two balls are selected at random from the bag, one after the other, with replacement, find the probability that the first is red and the second is blue

A. \(\frac{2}{9}\)
B. \(\frac{5}{18}\)
C. \(\frac{20}{81}\)
D. \(\frac{5}{9}\)

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Correct Answer: Option C

Explanation

n(red balls) = 5

n(blue balls) = 4

n(\(\iff\)) = 9

Hence, prob (R₁, B₂)

= \(\frac{5}{9} \times \frac{4}{9}\)

= \(\frac{20}{81}\)

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A bag contains 5 red and 4 blue identical balls. Id two balls are selected...

Correct Answer: Option C

Explanation

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