A variable y is inversely proportional to x\(^2\), when y = 10, x = 2. What is y when x = 10?
y \(\alpha\) \(\frac{1}{x^2}\)
y = \(\frac{k}{x^2}\)
k = x\(^2\)y
= (2)\(^2\) x 10 = 40
y = \(\frac{40}{x^2}\)
= \(\frac{40}{(10)^2}\)
= \(\frac{40}{100}\) = 0.4
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