The solution to the simultaneous equations 3x + 5y = 4, 4x + 3y =...

Mathematics

JAMB 1982

The solution to the simultaneous equations 3x + 5y = 4, 4x + 3y = 5 is

A. (\(\frac{-13}{11}, \frac{1}{11}\))
B. (\(\frac{13}{11}, \frac{1}{11}\))
C. (\(\frac{13}{11}, \frac{-1}{11}\))
D. (\(\frac{11}{13}, \frac{1}{11}\))
E. (13, 11)

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Correct Answer: Option B

Explanation

3x + 5y = 4, 4x + 3y = 5

3x + 5y = 4 x 4

4x + 3y = 5 x 3

12x + 20y = 16.....(i)

12x + 9y = 15.......(ii)

subtract eqn.(ii) from eqn.(i)

11y = 1

y = \(\frac{1}{11}\)

12x + 20 x \(\frac{1}{11}\) = 16

12x = \(\frac{156}{11}\)

x = \(\frac{13}{11}\)

= \(\frac{13}{11}, \frac{1}{11}\)

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