Correct Answer: Option C

Explanation

log10 a\(\frac{1}{3}\) + \(\frac{1}{4}\)log10 a - \(\frac{1}{12}\)log10a7 = log10 a\(\frac{1}{3}\) + log10\(\frac{1}{4}\) - log10 a\(\frac{7}{12}\)

= log\(_{10}\) a\(\frac{7}{12}\) - log\(_{10}\) a\(\frac{7}{12}\)

= log\(_{10}\) 1 = 0

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