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If sin \(\theta\) = \(\frac{x}{y}\) and 0o < 90o then find \(\frac{1}{tan\theta}\)

Mathematics
JAMB 1984

If sin \(\theta\) = \(\frac{x}{y}\) and 0o < 90o then find \(\frac{1}{tan\theta}\)
  • A. \(\frac{x}{\sqrt{y^2 - x^2}}\)
  • B. \(\frac{y}{x}\)
  • C. \(\frac{\sqrt{y^2 + x^2}}{y^2 - x^2}\)
  • D. \(\frac{y^2 - x^2}{x}\)
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Correct Answer: Option D
Explanation
\(\frac{1}{tan\theta}\) = \(\frac{cos\theta}{sin\theta}\)

sin\(\theta\) = \(\frac{x}{y}\)

cos\(\theta\) = \(\frac{\sqrt{y^2 - x^2}}{y}\)

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