Correct Answer: Option C

Explanation

Pq + 1 = q²......(i)

t = \(\frac{1}{p}\) - \(\frac{1}{pq}\).........(ii)

p = \(\frac{q^2 - 1}{q}\)

Sub for p in equation (ii)

t = \(\frac{1}{q^2 - \frac{1}{q}}\) - \(\frac{1}{\frac{q^2 - 1}{q} \times q}\)

t = \(\frac{q}{q^2 - 1}\) - \(\frac{1}{q^2 - 1}\)

t = \(\frac{q - 1}{q^2 - 1}\)

= \(\frac{q - 1}{(q + 1)(q - 1)}\)

= \(\frac{1}{q + 1}\)

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