Correct Answer: Option A

Explanation

cos\(\theta\) = \(\frac{a}{b}\), Sin\(\theta\) = \(\sqrt{\frac{b^2 - a^2}{a}}\)

Tan\(\theta\) = \(\sqrt{\frac{b^2 - a^2}{a^2}}\), Tan ² = \(\sqrt{\frac{b^2 - a^2}{a^2}}\)

1 + tan²\(\theta\) = 1 + \(\frac{b^2 - a^2}{a^2}\)

= \(\frac{a^2 + b^2 - a^2}{a^2}\)

= \(\frac{b^2}{a^2}\)

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