Correct Answer: Option B

Explanation

\(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\)
\(\frac{1}{x-3}-\frac{3(x-1)}{(x-3)(x+3)}\)
\(\frac{x+3-3x+3}{(x-3)(x+3)};\frac{-2x+6}{(x-3)(x+3)}\)
\(\frac{-2(x-3)}{(x-3)(x+3)}=\frac{-2}{x+3}\)

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