Given that x = -\(\frac{1}{2}\) and y = 4 evaluate 3x\(^2y+xy^2\)
\(x = -\frac{1}{2}\), y = 4 3x\(^2\)y + xy\(^2\) 3\(\left[-\frac{1}{2}\right]^2 \times 4 + \left(\frac{-1}{2}\right)(4)^2\) 3\(\times \frac{1}{4} \times 4 -\frac{1}{2} \times 16\) 3 - 8 = -5
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