If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?

If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?
• A. (5/2)
• B. -(5/4)
• C. -(25/4)
• D. -10
Explanation
Hint: apply basic mathematics rules beginning from BODMAS to algebra, and follow solution carefully to arrive at p =(5/2), q = -(25/4) and r = -(9/2).

Then p+2q will give you $$\frac{5}{2}+2\left(\frac{-25}{4}\right)= -10$$

Contributions (61)

using the laws of indices u get the values of p=5/2, q=-25/4 and r=-17/4 then you solve p +2q which gives -10
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• Jesus is Lord: You are absolutely correct! you go school well well.
4 years ago
• alaleyo damilola: i dnt understand it very wel
3 years ago
Here is an explanation:

To solve this, it is simple though the question looks more complex.

Solution

(a^2 b^2 c)^3\4 divided by a^-1 b^4 c^5 equals to a^p b^q c^r.

First let's separate the question, let's put aside the equals to part, now

Multiply all the numerator through by the power of 3/4. You will get a^3/2 b^-9/4 c^3/4 after this, use law of indices to divide the numerator with the denominator so we have a^3/2 ÷ a^-1 b^-9/4 ÷ b^4 c^3/4 ÷ c^5 after using law of indices to solve it, you will get a^5/2 b^-25/4 c^-17/4. So after these we get our p,q,r by comparing the powers.

:. a^5/2 b^-25/4 c^-17/4 = a^p b^q c^r, so p = 5/2, q = -25/4 c = -17/4. So now P + 2Q = 5/2 + 2(-25/4) after solving this, you will get -10 which is the answer.

Thank you.

REF: Jamb, 1999
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d question self is confusing
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guys pls i reall need sombody to put me true all this thing, cus i do not understant
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God help me in my exam
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This seems hard but using the laws of indices, it'll look so freaking easy, that triumphant feelin you get when you solve something right :D
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upgrade in the explanation skills.
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thanks waldon
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This question is really great.what you need to do first is to open the bracket then use indices to remove the division sign to subtraction sign then after which you compare to get p,q and r.then u can substitute it into p+2q.that's it.you just need to tink hard.
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after breaking it with the law indices u will get a^5/2 b^-25/4 c^-17/4 note: that the question ask for this p+2q=? knowing that a^p b^q c^r than fix in the value when p=5/2 and q=-25/4.in solving 5/2+2(-25/4)=-10 as the answer.
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Dis site is very interesting but please ur questions is nt clearly seen,,i lv u.
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dnt even undastand d qstion
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a^6/4b^-9/4c^3/4 for d numerator wen u multiply 3/4 For d denominator q^-1b^4c^5

Apply the law of indices u will gt a^10/4b^-25/4c^-17/4(In a^p b^q c^r)

but the questn is d value of p+2q i.e p=10/4 q=-25/4 Substitute it in p+2q so 10/4+2(-25/4)=10/4-50/4 =40/4=-10
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