If \(\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}\) What is the value of p+2q?
Hint: apply basic mathematics rules beginning from BODMAS to algebra, and follow solution carefully to arrive at p =(5/2), q = -(25/4) and r = -(17/4).
Then p+2q will give you \(\frac{5}{2}+2\left(\frac{-25}{4}\right)= -10\)
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7 years ago
[a^2(3/4)b^-3(3/4)c^(3/4)]divided by (a^-1b^4c^5)
===>(a^3/2b^-9/4c^3/4)divided by (a^-1b^4c^5).
Note a^p =3/2-(-1)==>p=5/2
q=-9/4-(4)===>q=-25/4
r=3/4-(5)===>r=-17/4
now p+2q
5/2+2(-25/4)
:- p+2q=-10.
Make use of indice...