### If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?

If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?
• A. (5/2)
• B. -(5/4)
• C. -(25/4)
• D. -10
##### Explanation
Hint: apply basic mathematics rules beginning from BODMAS to algebra, and follow solution carefully to arrive at p =(5/2), q = -(25/4) and r = -(9/2).

Then p+2q will give you $$\frac{5}{2}+2\left(\frac{-25}{4}\right)= -10$$

#### Contributions (62)

8 months ago
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Waliu
8 months ago
na wa day say we should come and be completing with this artificial intelligence( computer) which is suppose to be done by an artificial work done ( dat is robot ) u cant win onless u too are robot,
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OLAMIPLENTY
11 months ago
God help me in my exam
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Alwayz
2 years ago
Here is an explanation:

To solve this, it is simple though the question looks more complex.

Solution

(a^2 b^2 c)^3\4 divided by a^-1 b^4 c^5 equals to a^p b^q c^r.

First let's separate the question, let's put aside the equals to part, now

Multiply all the numerator through by the power of 3/4. You will get a^3/2 b^-9/4 c^3/4 after this, use law of indices to divide the numerator with the denominator so we have a^3/2 梅 a^-1 b^-9/4 梅 b^4 c^3/4 梅 c^5 after using law of indices to solve it, you will get a^5/2 b^-25/4 c^-17/4. So after these we get our p,q,r by comparing the powers.

:. a^5/2 b^-25/4 c^-17/4 = a^p b^q c^r, so p = 5/2, q = -25/4 c = -17/4. So now P + 2Q = 5/2 + 2(-25/4) after solving this, you will get -10 which is the answer.

Thank you.

REF: Jamb, 1999
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ruthbaiby
3 years ago
the answer is c ; be it -25/4 or -13/2
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Reallateco
3 years ago
I tink the question is not correct
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WALIULLAH
3 years ago
upgrade in the explanation skills.
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austinohio
3 years ago
d question self is confusing
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Tsinealabi
3 years ago
Finally i got the answer
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prof kc
3 years ago
is this really jamb pst questions?
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charles obeta
3 years ago
gud one
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Yaks SG
3 years ago
Laughing data
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sunday felicia
3 years ago
I SWEAR HEE NO EASY AT ALL.IS DIS D KIND OF QUESTION WE ARE GOIN TO FACE INSIDE HALL. BEFORE I FINISHE SOLVING DIS QUESTION INSIDE EXAM HALL,DERE WOULD BE ANYTIME LEFT.MAY GOD HELP US NI O
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• suntoozee: abi na he no easy at all,, person suppose to agonize b4 solving it.
1 year ago
• Favour: u are right may God help us.
10 months ago
• Kenny: i dey tell u
8 months ago
viole3t@valerie
4 years ago
i dnt understand any of the solution pls help
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odince
4 years ago
Which kin question b dis. Wats d meanin of \, /, {, }, confusion occupying my brain.
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