Correct Answer: Option D

Explanation

Midpoint between P(4, 5) and Q(-6, -1) = \(\frac{4 - 6}{2}, \frac{5 - 1}{2} = (-1, 2)\)

Gradient of PQ = \(\frac{5 - (-1)}{4 - (-6)} = \frac{3}{5}\)

Gradient of line perpendicular to PQ = \(\frac{-1}{\frac{3}{5}} = -\frac{5}{3}\)

\(line = \frac{y - 2}{x + 1} = \frac{-5}{3}\)

\(3y - 6 = -5x - 5\)

\(5x + 3y - 6 + 5 = 0 \implies 5x + 3y - 1 = 0\)

• heat energy? Answer this

  2 Answers   ·   Physics   ·   1 year ago
• a ship sails 340km in direction 225⁰, then sails 570km in the direction 035⁰. how far is the final position... Answer this

  2 Answers   ·   Mathematics   ·   2 days ago
• Calculate the mass of iron (ii) sulphide required to react with dilute HCl to provide 112cm3 of H2S gas at... Answer this

  3 Answers   ·   5 years ago