Forces of magnitude 8N and 5N act on a body as shown above. Calculate, correct to 2 dp, the angle that the resultant makes with the horizontal.
| x - component | y - component | |
| 8N | 8sin 45 =5.657 | 8cos45 =5.657 |
| 5N | 5cos30 = - 4.330 | 5sin30 = 2.5 |
| 1.327 | 8.157 |
Resultant force = \(\sqrt{(8.157)^2 + (1.327)^2}\) = \(\sqrt{68.299}\) = 8.264
Cos\(\theta\) = \(\frac{adj}{hyp}\) = \(\frac{1.327}{8.264}\) = 0.160576
\(\theta\) = cos\(^{-1}\)(0.160576) = 80.76º
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