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C\(_6\)H\(_{12}\)O\(_6\) What is the molar mass of the compound above? [ H=1, C=12, O=16 }

Chemistry
NECO 2009

C\(_6\)H\(_{12}\)O\(_6\)

What is the molar mass of the compound above?

[ H=1, C=12, O=16 }

  • A. 45
  • B. 61
  • C. 180
  • D. 123
  • E. 244
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Correct Answer: Option C
Explanation

The compound above is identified as glucose

Carbon - 12 \(\times\) 6 atoms present

Hydrogen - 1 \(\times\) 12 atoms present

Oxygen - 16 \(\times\) 6 atoms present

= 72 + 12 + 96

= 180


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